Optimal. Leaf size=132 \[ -\frac{b^4 (A (2-n)+C (3-n)) \sin (c+d x) (b \sec (c+d x))^{n-4} \text{Hypergeometric2F1}\left (\frac{1}{2},\frac{4-n}{2},\frac{6-n}{2},\cos ^2(c+d x)\right )}{d (2-n) (4-n) \sqrt{\sin ^2(c+d x)}}-\frac{b^3 C \tan (c+d x) (b \sec (c+d x))^{n-3}}{d (2-n)} \]
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Rubi [A] time = 0.143475, antiderivative size = 132, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.129, Rules used = {16, 4046, 3772, 2643} \[ -\frac{b^4 (A (2-n)+C (3-n)) \sin (c+d x) (b \sec (c+d x))^{n-4} \, _2F_1\left (\frac{1}{2},\frac{4-n}{2};\frac{6-n}{2};\cos ^2(c+d x)\right )}{d (2-n) (4-n) \sqrt{\sin ^2(c+d x)}}-\frac{b^3 C \tan (c+d x) (b \sec (c+d x))^{n-3}}{d (2-n)} \]
Antiderivative was successfully verified.
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Rule 16
Rule 4046
Rule 3772
Rule 2643
Rubi steps
\begin{align*} \int \cos ^3(c+d x) (b \sec (c+d x))^n \left (A+C \sec ^2(c+d x)\right ) \, dx &=b^3 \int (b \sec (c+d x))^{-3+n} \left (A+C \sec ^2(c+d x)\right ) \, dx\\ &=-\frac{b^3 C (b \sec (c+d x))^{-3+n} \tan (c+d x)}{d (2-n)}+\left (b^3 \left (A+\frac{C (3-n)}{2-n}\right )\right ) \int (b \sec (c+d x))^{-3+n} \, dx\\ &=-\frac{b^3 C (b \sec (c+d x))^{-3+n} \tan (c+d x)}{d (2-n)}+\left (b^3 \left (A+\frac{C (3-n)}{2-n}\right ) \left (\frac{\cos (c+d x)}{b}\right )^n (b \sec (c+d x))^n\right ) \int \left (\frac{\cos (c+d x)}{b}\right )^{3-n} \, dx\\ &=-\frac{\left (A+\frac{C (3-n)}{2-n}\right ) \cos ^4(c+d x) \, _2F_1\left (\frac{1}{2},\frac{4-n}{2};\frac{6-n}{2};\cos ^2(c+d x)\right ) (b \sec (c+d x))^n \sin (c+d x)}{d (4-n) \sqrt{\sin ^2(c+d x)}}-\frac{b^3 C (b \sec (c+d x))^{-3+n} \tan (c+d x)}{d (2-n)}\\ \end{align*}
Mathematica [A] time = 0.24919, size = 118, normalized size = 0.89 \[ \frac{b \sqrt{-\tan ^2(c+d x)} \cot (c+d x) (b \sec (c+d x))^{n-1} \left (A (n-1) \cos ^2(c+d x) \text{Hypergeometric2F1}\left (\frac{1}{2},\frac{n-3}{2},\frac{n-1}{2},\sec ^2(c+d x)\right )+C (n-3) \text{Hypergeometric2F1}\left (\frac{1}{2},\frac{n-1}{2},\frac{n+1}{2},\sec ^2(c+d x)\right )\right )}{d (n-3) (n-1)} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 1.328, size = 0, normalized size = 0. \begin{align*} \int \left ( \cos \left ( dx+c \right ) \right ) ^{3} \left ( b\sec \left ( dx+c \right ) \right ) ^{n} \left ( A+C \left ( \sec \left ( dx+c \right ) \right ) ^{2} \right ) \, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (C \sec \left (d x + c\right )^{2} + A\right )} \left (b \sec \left (d x + c\right )\right )^{n} \cos \left (d x + c\right )^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (C \cos \left (d x + c\right )^{3} \sec \left (d x + c\right )^{2} + A \cos \left (d x + c\right )^{3}\right )} \left (b \sec \left (d x + c\right )\right )^{n}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (C \sec \left (d x + c\right )^{2} + A\right )} \left (b \sec \left (d x + c\right )\right )^{n} \cos \left (d x + c\right )^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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